Remember, to find the equation of a line you need a point \((a,b)\) and the gradient \(m\). This determines the gradient of the required line. Use B\((6,3)\) and \(m\). The perpendicular bisector ...

Find the equation of the line perpendicular to \(AB\) where \(A = (1,5)\) and \(B = (3, - 8)\) and passing through the midpoint of AB. Now that we have the gradient, we next need to find the ...